C dw 1234h 0ffh
Weba. 1,20 b. 2,10 c. 3,30 d. 1,25 正确答案:a 大工 17 春《微机原理与控制技术》在线作业 3 二、判断题(共 10 道试题,共 50 分。 ) 1. 外部存储器通常是通过总线接口电路与系统总线相连,速度较慢,容量较大,价格较低, 用于存放计算机当前暂时不用的程序、数据或 ... Web有一道微机原理的题, 已知程序的数据段为: data segment a db 'a',10h b db 'computer' c dw 1234h,offh d db 5dup(?) e dd 1200459ah data ends 下列程序执行后,每条指令后的寄存 …
C dw 1234h 0ffh
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WebThis problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. See Answer See Answer See Answer done loading WebHow to convert from hex to decimal. A regular decimal number is the sum of the digits multiplied with power of 10. 137 in base 10 is equal to each digit multiplied with its corresponding power of 10: 137 10 = 1×10 2 +3×10 1 +7×10 0 = 100+30+7. Hex numbers are read the same way, but each digit counts power of 16 instead of power of 10.
WebMOV AL, 0FFh ; AL = 0FFh (-1) DAS ; AL = 99h, CF = 1 RET : DEC REG memory: Decrement. Algorithm: operand = operand - 1 ... ORG 100h LDS AX, m RET m DW 1234h DW 5678h END AX is set to 1234h, DS is set to 5678h. LEA REG, memory Load Effective Address. Algorithm: REG = address of memory (offset) ... Web已知程序的数据段为: DATA SEGMEnT A DB ‘$’,10H B DB ‘coMPUTER’ c DW 1234H, 0FFH D DB 5 DUP (?) E DD 1200459AH DATA EnDS 求下列程序段执行后的结果是什么 …
WebNov 7, 2024 · .model small .data opr1 dw 1234h opr2 dw 0002h result dw 01 dup(?),\'$\' .code mov ax,@data mov ds,ax mov ax,opr1... Level up your programming skills with …
Web已知程序的数据段为data segment. 有一道微机原理的题,已知程序的数据段为:DATASEGMENTADB'A',10HBDB'COMPUTER'CDW1234H,OFFHDDB5DUP (?)EDD1200459AHDATAENDS下列程序执行后,每条指令后的寄存器的内容是什么?MOVAL,A;... #热议# 「捐精」的筛选条件是什么?.
WebStudy with Quizlet and memorize flashcards containing terms like 21. The following statement will assemble without errors: mov WORD PTR [eax], 1234h, 22. The following instruction will produce FFFFFFFCh in EAX: movsx eax,-4, 23. The SAHF instruction copies the Sign, Overflow, and Carry flags to the AL register. and more. touch profileWebORG 100h MOV AL, var1 MOV BX, var2 RET ; stops the program. VAR1 DB 7 var2 DW 1234h Copy the above code to the source editor, and press F5 key to compile it and load in the emulator. You should get something like: ... c DB 5 DUP(9) is an alternative way of declaring: c DB 9, 9, 9, 9, 9 one more example: d DB 5 DUP(1, 2) touch program enrollment formWeb2024年河北专接本微机原理与接口(含汇编语言)模拟试卷(3) 河北省普通高校专科接本科教育考试微机原理与接口(含汇编语言)模拟试卷七(考试时间:75 分钟)(总分:150 分)说明:请在答题纸的相应位置上作答,在其它位置上作答的无效。一、单项选择题(本大题共 15 小题,每小题 3 分,共 45 分。 touch professional cosmeticsWebJul 3, 2024 · C DW 1234H,0FFH D DB 5DUP(?) E DD1200459AH ... 练习 在C语言中,我们知道常见的数据类型有char、short、int 、long、long long、float、double等,以及它们所占的存储空间大小:数据类型基础知识 而这些类型的意义在于: 使用这个类型开辟内存空间的大小(大小决定了使用范围 ... pottawatomie golf st charles ilWebNov 7, 2024 · .model small .data opr1 dw 1234h opr2 dw 0002h result dw 01 dup(?),\'$\' .code mov ax,@data mov ds,ax mov ax,opr1... Level up your programming skills with exercises across 52 languages, and insightful discussion with our dedicated team of welcoming mentors. Level up your programming skills with exercises across 52 … pottawatomie golf course st charlesWebQuestion: Source code Register Window DATA EQU 10h DW 1234h, 5678h, 0ABCDh,-1 DB OAH DD? EAX = ABCDEF01 EBX 00000024 ECX = 00000015 EDX = 00000005 … touch program filesWebApr 12, 2024 · a dw 1234h b dw 5678h push a push b pop a pop b 试回答:上述程序段执行后(a)= 5678h ,(b)= 1234h 2. 分析下面程序段, MOV AL,200 SAR AL,1 MOV BL,AL MOV CL,2 SAR AL,CL ADD AL,BL 试问程序段执行后(BL)= 0E4H (AL)= 0DDH 3. pottawatomie golf st charles